0%

### 题目描述

Suppose an array of length `n` sorted in ascending order is rotated between `1` and `n` times. For example, the array `nums = [0,1,4,4,5,6,7]` might become:

• `[4,5,6,7,0,1,4]` if it was rotated 4 times.
• `[0,1,4,4,5,6,7]` if it was rotated 7 times.

Notice that rotating an array `[a, a, a, ..., a[n-1]]` 1 time results in the array `[a[n-1], a, a, a, ..., a[n-2]]`.

Given the sorted rotated array `nums` that may contain duplicates, return the minimum element of this array.

### 例子

#### 例子 1

Input: `nums = [1,3,5]`
Output: `1`

#### 例子 2

Input: `nums = [2,2,2,0,1]`
Output: `0`

### Constraints

• `n == nums.length`
• `1 <= n <= 5000`
• `-5000 <= nums[i] <= 5000
• `nums` is sorted and rotated between `1` and `n` times.

This is the same as `Find Minimum in Rotated Sorted Array` but with duplicates. Would allow duplicates affect the run-time complexity? How and why?

### 解题思路

• 时间复杂度: `O(log n) -> O(n)`
• 空间复杂度: `O(1)`

GitHub 代码同步地址： 154.FindMinimumInRotatedSortedArrayIi.cpp

GitHub: Leetcode-C++-Solution